描述:给定链表 head,对于每个节点,查找其右侧第一个值严格大于它的节点。返回整数数组 answer,answer[i] 为第 i 个节点的下一个更大节点值;若无,则为 0。
res[i] = stack.length ? stack.at(-1) : -1;
,更多细节参见搜狗输入法2026
Deborah Alsina, chief executive of Arthritis UK, said: "This is a crushing blow for those individuals who have finally made it to the front of the orthopaedic surgery queue after a long time waiting.
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